# What is the standard form of y=(x-1)(x - 7) ?

May 29, 2018

See a solution process below:

#### Explanation:

To write this equation in standard form we must multiply the two terms on the right side of the equation by multiplying each individual term in the left parenthesis by each individual term in the right parenthesis.

$y = \left(\textcolor{red}{x} - \textcolor{red}{1}\right) \left(\textcolor{b l u e}{x} - \textcolor{b l u e}{7}\right)$ becomes:

$y = \left(\textcolor{red}{x} \times \textcolor{b l u e}{x}\right) - \left(\textcolor{red}{x} \times \textcolor{b l u e}{7}\right) - \left(\textcolor{red}{1} \times \textcolor{b l u e}{x}\right) + \left(\textcolor{red}{1} \times \textcolor{b l u e}{7}\right)$

$y = {x}^{2} - 7 x - 1 x + 7$

We can now combine like terms:

$y = {x}^{2} + \left(- 7 - 1\right) x + 7$

$y = {x}^{2} + \left(- 8\right) x + 7$

$y = {x}^{2} - 8 x + 7$