What is the standard form of $y= (x + 10)(x – 4)$ ?

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Answer 1 · 2016-01-06T23:25:35

$x^2 + 6x - 40$

to obtain the standard form multiply the brackets out

x(x - 4 ) + 10 (x - 4 )

$= x^2 - 4x + 10x - 40$

$= x^2 + 6x - 40$

What is the standard form of y= (x + 10)(x – 4) y= (x + 10)(x – 4) ?