# What is the standard form of y= (x-12) (x+3) ?

Jan 30, 2016

${x}^{2} - 9 x - 36$

#### Explanation:

Each term in the 2nd bracket must be multiplied by each term
in the 1st bracket.

This can be done as : x (x+3) - 12(x+3)

distribute : ${x}^{2} + 3 x - 12 x - 36$

collect 'like terms' : ${x}^{2} - 9 x - 36$