# What is the standard form of  y= (x+13)(x-4)(x-1)?

Nov 17, 2015

$y = {x}^{3} + 8 {x}^{2} - 61 x + 52$

#### Explanation:

Standard form places the powers of $x$ in descending sequence.

$\left(x + 13\right) \left(x - 4\right) \left(x - 1\right)$

$= {x}^{3} + \left(13 - 4 - 1\right) {x}^{2} + \left(\left(13 \times - 4\right) + \left(13 \times - 1\right) + \left(- 4 \times - 1\right)\right) x + \left(13 \times - 4 \times - 1\right)$

$= {x}^{3} + 8 {x}^{2} - 61 x + 52$