What is the standard form of # y= (x+13)(x-4)(x-1)#?
1 Answer
Nov 17, 2015
Explanation:
Standard form places the powers of
#(x+13)(x-4)(x-1)#
#=x^3+(13-4-1)x^2+((13xx-4)+(13xx-1)+(-4xx-1))x+(13xx-4xx-1)#
#=x^3+8x^2-61x+52#
