What is the standard form of $y= (x+13)(x-4)(x-1)$ ?

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Answer 1 · 2015-11-17T22:04:50

$y = x^3+8x^2-61x+52$

Standard form places the powers of $x$ in descending sequence.

$(x+13)(x-4)(x-1)$

$=x^3+(13-4-1)x^2+((13xx-4)+(13xx-1)+(-4xx-1))x+(13xx-4xx-1)$

$=x^3+8x^2-61x+52$

What is the standard form of y= (x+13)(x-4)(x-1) y= (x+13)(x-4)(x-1)?