# What is the standard form of  y= (x+2)^2+ x(x-3)^2 ?

Jan 28, 2016

$y = {x}^{3} - 5 {x}^{2} + 13 x + 4$

#### Explanation:

Expand each polynomial through distribution.

$y = \left({x}^{2} + 2 x + 2 x + 4\right) + x \left({x}^{2} - 3 x - 3 x + 9\right)$

$y = \left({x}^{2} + 4 x + 4\right) + x \left({x}^{2} - 6 x + 9\right)$

$y = {x}^{2} + 4 x + 4 + {x}^{3} - 6 {x}^{2} + 9 x$

$y = {x}^{3} + \left({x}^{2} - 6 {x}^{2}\right) + \left(4 x + 9 x\right) + 4$

$y = {x}^{3} - 5 {x}^{2} + 13 x + 4$

This is in standard form since the terms' exponents are listed in descending order.