What is the standard form of # y= (x+2)^2+ x(x-3)^2 #?
1 Answer
Jan 28, 2016
Explanation:
Expand each polynomial through distribution.
#y=(x^2+2x+2x+4)+x(x^2-3x-3x+9)#
#y=(x^2+4x+4)+x(x^2-6x+9)#
#y=x^2+4x+4+x^3-6x^2+9x#
#y=x^3+(x^2-6x^2)+(4x+9x)+4#
#y=x^3-5x^2+13x+4#
This is in standard form since the terms' exponents are listed in descending order.
