Question

What is the standard form of `y= (x-2)(2x^2-3x)-7`?

Answer 1

`y=2x^3-7x^2+6x-7`

Explanation:

Start from the given equation then multiply the two binomials then combine like terms to simplify

`y=(x-2)(2x^2-3x)-7`

`y=2x^3-3x^2-4x^2+6x-7`

`y=2x^3-7x^2+6x-7`

God bless....I hope the explanation is useful.