What is the standard form of $y= (x-2)(2x^2-3x)-7$ ?

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Answer 1 · 2016-04-16T02:51:34

$y=2x^3-7x^2+6x-7$

Start from the given equation then multiply the two binomials then combine like terms to simplify

$y=(x-2)(2x^2-3x)-7$

$y=2x^3-3x^2-4x^2+6x-7$

$y=2x^3-7x^2+6x-7$

God bless....I hope the explanation is useful.

What is the standard form of y= (x-2)(2x^2-3x)-7y= (x-2)(2x^2-3x)-7?