What is the standard form of $y = {(x^{2} + 3)}^{2}$ $y=(x^2 + 3)^2$ ?

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Answer 1 · 2016-01-12T21:27:41

$x^{4} + 6 x^{2} + 9$ $x^4 + 6x^2 +9$

To write in standard form expand the brackets and collect like terms.

${(x^{2} + 3)}^{2} = (x^{2} + 3) (x^{2} + 3) = x^{2} (x^{2} + 3) + 3 (x^{2} + 3)$ $(x^2 + 3 )^2 = (x^2 + 3 )(x^2 + 3 ) = x^2(x^2 + 3 ) + 3(x^2 + 3 )$

multiply out brackets : $x^{4} + 3 x^{2} + 3 x^{2} + 9 = x^{4} + 6 x^{2} + 9$ $x^4 + 3x^2 +3x^2 + 9 = x^4 + 6x^2 + 9$

What is the standard form of y=(x2+3)2y=(x^2 + 3)^2 ?