# What is the standard form of y=(x^2 + 3)^2 ?

${x}^{4} + 6 {x}^{2} + 9$
${\left({x}^{2} + 3\right)}^{2} = \left({x}^{2} + 3\right) \left({x}^{2} + 3\right) = {x}^{2} \left({x}^{2} + 3\right) + 3 \left({x}^{2} + 3\right)$
multiply out brackets : ${x}^{4} + 3 {x}^{2} + 3 {x}^{2} + 9 = {x}^{4} + 6 {x}^{2} + 9$