What is the standard form of $y = (x + 2) (4 x + 10) - x^{2} - 5 x$ $y= (x+2)(4x+10)-x^2-5x$ ?

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What is the standard form of $y = (x + 2) (4 x + 10) - x^{2} - 5 x$ $y= (x+2)(4x+10)-x^2-5x$ ?

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Answer 1 · 2018-05-24T14:10:20

$3 x^{2} + 13 x + 20$ $3x^2+13x+20$

Explanation:

expanding $(x + 2) (4 x + 10) = 4 x^{2} + 18 x + 20$ $(x+2)(4x+10)=4x^2+18x+20$
and adding $- x^{2} - 5 x$ $-x^2-5x$
we get
$3 x^{2} + 13 x + 20$ $3x^2+13x+20$

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What is the standard form of $y = (x + 2) (4 x + 10) - x^{2} - 5 x$ $y= (x+2)(4x+10)-x^2-5x$ ?

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Explanation:

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What is the standard form of y= (x+2)(4x+10)-x^2-5xy=(x+2)(4x+10)−x2−5x y= (x+2)(4x+10)-x^2-5x?

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Explanation:

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What is the standard form of $y = (x + 2) (4 x + 10) - x^{2} - 5 x$ $y= (x+2)(4x+10)-x^2-5x$ ?