What is the standard form of #y= (x-2) (x+3) #?

1 Answer
Jan 31, 2016

Standard form is #y=ax^2+bx+c#. To convert #y=(x-2)(x+3)# into standard form, use the 'FOIL' rule. The result is: #y=x^2 + x - 6#

Explanation:

To convert #y=(x-2)(x+3)# into standard form, use the FOIL rule. It stands for firsts, outers, inners, lasts, and just reminds us of how to make sure we remember to multiply each thing in the first bracket by everything in the second:

Firsts #(x xx x)#, outers #(x xx 3)#, inners #(x xx -2)#, lasts #(-2 xx 3)#:

#y=x^2 + 3x - 2x -6#

Collect like terms:

#y= x^2 + x - 6#