What is the standard form of y=x^2(x+4)(x-5) -x^2? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Tamir E. Nov 23, 2017 y=x^2(x^2-x-21) or y=x^4-x^3-21x^2 Explanation: y=x^2(x+4)(x-5)-x^2= =x^2[(x+4)(x-5)-1]= =x^2[x^2-x-20-1]= =x^2[x^2-x-21]= =x^4-x^3-21x^2 Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is x^2+3x^{\frac{1}{2}} a polynomial? How do you express -16+5f^8-7f^3 in standard form? What is the degree of 16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2? What is the degree of the polynomial x^4-3x^3y^2+8x-12? What is the difference between a monomial, binomial and polynomial? How do you write y = 2/3x + 5 in standard form? See all questions in Polynomials in Standard Form Impact of this question 1321 views around the world You can reuse this answer Creative Commons License