What is the standard form of y= (x + 2)(x + 5)y=(x+2)(x+5)?

2 Answers
Dec 1, 2015

y=x^2+7x+10y=x2+7x+10

Explanation:

The "standard form" for a quadratic is (in general)
color(white)("XXX")y=ax^2+bx+cXXXy=ax2+bx+c
with constants a, b, and ca,b,andc

Dec 1, 2015

y=x^2+7x+10y=x2+7x+10
Look at the method. It is using something called the 'Distributive' law

Explanation:

Given y= (color(green)(x)color(red)(+)color(blue)(2))(x+5)y=(x+2)(x+5)

y=color(green)(x)(x+5) color(red)(+)color(blue)(2)(x+5)y=x(x+5)+2(x+5)

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Notice that the sign of the color(blue)( 2)2 follows it.
If the sign had been negative then we would have color(red)(-)color(blue)(2)(x+5)2(x+5)
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y=(color(green)(x) xx x)+(color(green)(x) xx5)color(white)(....)+color(white)(....)(color(blue)(2) xx x)+(color(blue)(2)xx5)

y=x^2+5x+2x+10

y=x^2+7x+10