What is the standard form of y=(x-3)^2+3y=(x−3)2+3?
1 Answer
Explanation:
Multiply out the brackets and collect like terms.
(x - 3)^2 = (x - 3 )(x - 3 ) = x^2 - 3x - 3x + 9 (x−3)2=(x−3)(x−3)=x2−3x−3x+9
rArr y = x^2 - 6x + 9 + 3 = x^2 - 6x + 12 ⇒y=x2−6x+9+3=x2−6x+12 Writing an answer in standard form means , start with the term that has the highest power of the variable , in this case
x^2x2
Followed by terms with decreasing powers until the last term , usually a constant.
