What is the standard form of #y=(x-3)^2+3#?
1 Answer
Explanation:
Multiply out the brackets and collect like terms.
# (x - 3)^2 = (x - 3 )(x - 3 ) = x^2 - 3x - 3x + 9 #
#rArr y = x^2 - 6x + 9 + 3 = x^2 - 6x + 12 # Writing an answer in standard form means , start with the term that has the highest power of the variable , in this case
# x^2#
Followed by terms with decreasing powers until the last term , usually a constant.
