# What is the standard form of y=(x-3)^2+3?

##### 1 Answer
Mar 18, 2016

$y = {x}^{2} - 6 x + 12$

#### Explanation:

Multiply out the brackets and collect like terms.

${\left(x - 3\right)}^{2} = \left(x - 3\right) \left(x - 3\right) = {x}^{2} - 3 x - 3 x + 9$

$\Rightarrow y = {x}^{2} - 6 x + 9 + 3 = {x}^{2} - 6 x + 12$

Writing an answer in standard form means , start with the term that has the highest power of the variable , in this case ${x}^{2}$
Followed by terms with decreasing powers until the last term , usually a constant.