# What is the standard form of  y=x^3(9x^2-x-3) ?

Jul 9, 2018

$9 {x}^{5} - {x}^{4} - 3 {x}^{3}$

#### Explanation:

Let's start by distributing the ${x}^{3}$ to all terms. Remember, when we multiply exponents, we add the powers. We get

$9 {x}^{5} - {x}^{4} - 3 {x}^{3}$

Since our exponents are in order of descending degree, we are in standard form!

Hope this helps!