What is the standard form of $y = x^{3} (x^{2} - 16)$ $y=x^3(x^2 - 16)$ ?

Question

1334 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-04T19:01:04

$x^{5} - 16 x^{3}$ $x^5 - 16x^3$

expand bracket and write terms in descending powers of x.

$x^{3} \times x^{2} - x^{3} \times 16$ $x^3 xx x^2 - x^3 xx 16$

$= x^{5} - 16 x^{3}$ $= x^5 - 16x^3$

What is the standard form of y=x3(x2−16)y=x^3(x^2 - 16) ?