What is the standard form of #y=(x+3)(x^2 - 3x + 9) #?

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Answer 1 · 2016-05-23T00:07:18

#y=x^3 + 27#

We have

#y=(x+3)(x^2 - 3x + 9)# .

We need to expand this using the Distributive Property.

#y=(x+3)(x^2 - 3x + 9)#

#=x*(x^2 - 3x + 9) + 3*(x^2 - 3x + 9)# .

We multiply these through to get

#y=x^3 - 3x^2 + 9*x + 3*x^2 - 9x + 27# .

Collecting like terms we have

#y=x^3 + 27# .