What is the standard form of $y=(x+3)(x^2 - 3x + 9)$ ?

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Answer 1 · 2016-05-23T00:07:18

$y=x^3 + 27$

We have

$y=(x+3)(x^2 - 3x + 9)$ .

We need to expand this using the Distributive Property.

$y=(x+3)(x^2 - 3x + 9)$

$=x*(x^2 - 3x + 9) + 3*(x^2 - 3x + 9)$ .

We multiply these through to get

$y=x^3 - 3x^2 + 9*x + 3*x^2 - 9x + 27$ .

Collecting like terms we have

$y=x^3 + 27$ .

What is the standard form of y=(x+3)(x^2 - 3x + 9) y=(x+3)(x^2 - 3x + 9) ?