What is the standard form of $y = (x - 3) (x - 2) (x + 2)$ $y= (x - 3) (x - 2) (x + 2)$ ?

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What is the standard form of $y = (x - 3) (x - 2) (x + 2)$ $y= (x - 3) (x - 2) (x + 2)$ ?

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Answer 1 · 2016-01-11T22:11:09

$y = x^{3} - 3 x^{2} - 4 x + 12$ $y = x^3-3x^2-4x+12$

Explanation:

$y = (x - 3) (x - 2) (x + 2)$ $y = (x-3)(x-2)(x+2)$

$= (x - 3) (x^{2} - 4)$ $=(x-3)(x^2-4)$

$= x^{2} (x - 3) - 4 (x - 3)$ $=x^2(x-3)-4(x-3)$

$= x^{3} - 3 x^{2} - 4 x + 12$ $=x^3-3x^2-4x+12$

Standard form puts terms in decreasing order of degree as we have done here.

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What is the standard form of $y = (x - 3) (x - 2) (x + 2)$ $y= (x - 3) (x - 2) (x + 2)$ ?

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Explanation:

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What is the standard form of $y = (x - 3) (x - 2) (x + 2)$ $y= (x - 3) (x - 2) (x + 2)$ ?