What is the standard form of #y= (x-3)(x^3-5)-3x^4-5#?

1 Answer
Jun 4, 2017

Multiply through and collect like terms to find the solution:

#y=-2x^4-3x^3-5x+10#

Explanation:

#y=(x−3)(x^3−5)−3x^4−5#

Multiply the two sets of brackets using the 'FOIL - firsts, outers, inners, lasts' rule. It's a simple way to ensure that we don't forget any of the necessary multiplications:

#y=(x^4-3x^3-5x+15)−3x^4−5#

Now collect like terms to find the solution:

#y=-2x^4-3x^3-5x+10#

Note that the terms are written in decreasing orders of powers of #x#.