What is the standard form of y= (x+4)(2x-2)-(5x-2)^2y=(x+4)(2x−2)−(5x−2)2?

1 Answer
brigeee
May 25, 2018

y= -23x^2+26x-12y=−23x2+26x−12

Explanation:

y=(x+4)(2x-2)-(5x-2)^2y=(x+4)(2x−2)−(5x−2)2
y=x(2x-2)+4(2x-2)-[(5x-2)(5x-2)]y=x(2x−2)+4(2x−2)−[(5x−2)(5x−2)]
y=2x^2-2x+8x-8-[5x(5x-2)-2(5x-2)]y=2x2−2x+8x−8−[5x(5x−2)−2(5x−2)]
y=2x^2-2x+8x-8-[25x^2-20x+4]y=2x2−2x+8x−8−[25x2−20x+4]
y=2x^2-2x+8x-8-25x^2+20x-4y=2x2−2x+8x−8−25x2+20x−4
y=-23x^2+26x-12y=−23x2+26x−12
Hope this helps!

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