What is the standard form of # y= (x-5)(x-2)+(3x-1)^2#?

1 Answer
May 21, 2018

#y=10x²-13x+11#

See explanations below.

Explanation:

#y=(x-5)(x-2) +(3x-1)²#

The standard form of a polynomial is :
#y=sum_(k=0)^(n)a_kx^k=a_0+a_1x+...+a_nx^n#, where #a_k in RR# and #k in NN#.

In order to write it, you need to develop each term,
and to sum each term of same degree.

#y=(color(red)x-color(blue)5)(x-2)+(color(green)(3x)-color(purple)1)*(3x-1)#

#y=color(red)(x(x-2))-color(blue)(5(x-2))+color(green)(3x(3x-1))-color(purple)((3x-1))#

#y=color(red)(x*x-2*x)+(color(blue)(-5*x-5*(-2)))+color(green)(3x*3x-3x*1)-color(purple)((3x-1))#

#y=color(red)(x²-2x)-color(blue)(5x+10)+color(green)(9x²-3x)-color(purple)(3x+1)#

Finally, let's sum each term of same degree :

#y=(color(red)(1)color(green)(+9))^(color(orange)(=10))x²+(color(red)(-2)color(blue)(-5)color(green)(-3)color(purple)(-3))^(color(orange)(=-13))x(color(blue)(+10)color(purple)(+1))^(color(orange)(=11))#

#y=10x²-13x+11#

\0/ Here's our answer !