What is the standard form of y= (x-5)(x+6)^2 - (x-5)^2 (x+6)?

1 Answer
Sep 25, 2016

y = 11x^2+11x-330

Explanation:

y = (x-5)(x+6)^2 - (x-5)^2(x+6)

color(white)(y) = (x-5)(x+6)((x+6) - (x-5))

color(white)(y) = (x-5)(x+6)(color(red)(cancel(color(black)(x)))+6-color(red)(cancel(color(black)(x)))+5)

color(white)(y) = 11(x-5)(x+6)

color(white)(y) = 11(x^2+x-30)

color(white)(y) = 11x^2+11x-330