# What is the standard form of y= (x-6)^2+11?

Jun 13, 2018

$y = {x}^{2} - 12 x + 47$

#### Explanation:

Standard form of a quadratic is when the equation is given in the form:

$y = a {x}^{2} + b x + c$ where a, b and c are constants

To achieve, simply simplify the above equation

$y = \left(x - 6\right) \left(x - 6\right) + 11$
$y = {x}^{2} - 12 x + 36 + 11$
$y = {x}^{2} - 12 x + 47$