Question

What is the standard form of `y= (x-6)^2+11`?

Answer 1

`y=x^{2}-12x+47`

Explanation:

Standard form of a quadratic is when the equation is given in the form:

`y=ax^{2}+bx+c` where a, b and c are constants

To achieve, simply simplify the above equation

`y=(x-6)(x-6)+11`
`y=x^{2}-12x+36+11`
`y=x^{2}-12x+47`