# What is the standard form of  y= (x-6) (x+2) ?

the answer is ${x}^{2} - 4 x - 12$
to put something in standard form means to put it in order from exponent, then just $x$ then the number. so for this one, you have to distribute $x$ to the next $x$ and $2$ so you'll get ${x}^{2} + 2 x$ then the second number$- 6 x - 12$ you don't do the second number b/c it's the one being distributed to and plus it'll be the same. so now put it together and add like terms. ${x}^{2}$ is by itself. so do $+ 2 x - 6 x$ and $- 12$ is alone b/c there's nothing else like it. so you have ${x}^{2} - 4 x - 12$ and don't do $- 6 + 2$ so it EXACTLY like it is when you distribute