What is the standard form of # y= (x-6) (x-3) #?
1 Answer
Feb 7, 2016
Multiply out to find:
#y=x^2-9x+18#
Explanation:
We can use the FOIL mnemonic to help multiply this out:
#y = (x-6)(x-3)#
#=stackrel "First" overbrace(x*x) + stackrel "Outside" overbrace(x*(-3)) + stackrel "Inside" overbrace((-6)*x) + stackrel "Last" overbrace((-6)(-3))#
#=x^2-3x-6x+18#
#=x^2-9x+18#
This is in standard form with the powers of
