# What is the standard form of  y= (x - 8) (x + 4) ?

$y = {x}^{2} - 4 x - 32$
First, we multiply the first number from the first parenthesis with the numbers of the second parenthesis: $x . x + x . 4 = {x}^{2} + 4 x$.
Then, we multiply the second number from the first with the numbers of the second: $- 8 . x + \left(- 8\right) \text{ . } 4 = - 8 x - 32$.
Now, put them together: ${x}^{2} + 4 x - 8 x - 32$, that resumes in ${x}^{2} - 4 x - 32$