What is the standard form of # y= (x - 8) (x + 4) #?

1 Answer
Júlio B.
Dec 29, 2015

# y = x^2 - 4x -32 #

Explanation:

First, we multiply the first number from the first parenthesis with the numbers of the second parenthesis: # x . x + x . 4 = x^2 + 4x#.
Then, we multiply the second number from the first with the numbers of the second: # -8 . x + (-8) " . " 4 = -8x - 32 #.
Now, put them together: # x^2 +4x - 8x -32 #, that resumes in # x^2 -4x -32 #

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