Question

What is the standard form of `y= (x - 8) (x+4)`?

Answer 1

See a solution process below:

Explanation:

To put this equation in standard form we multiply the two terms on the right side of the equation by multiplying each individual term in the left parenthesis by each individual term in the right parenthesis.

`y = (color(red)(x) - color(red)(8))(color(blue)(x) + color(blue)(4))` becomes:

`y = (color(red)(x) xx color(blue)(x)) + (color(red)(x) xx color(blue)(4)) - (color(red)(8) xx color(blue)(x)) - (color(red)(8) xx color(blue)(4))`

`y = x^2 + 4x - 8x - 32`

We can now combine like terms:

`y = x^2 + (4 - 8)x - 32`

`y = x^2 + (-4)x - 32`

`y = x^2 - 4x - 32`