What is the standard form of # y= (x + 9) (x + 6) #?

1 Answer
May 10, 2018

#y=x^2+15x+54#

Explanation:

A quadratic formula given by #a(bx+c)(dx+e), e!="Euler's number"# will have a standard form equal to:
#abdx^2+a(cd+eb)x+ace# (this is given by expanding out the brackets:

Here:
#a=1#
#b=1#
#c=9#
#d=1#
#e=6#

So:
#y=(1*1*1)x^2+1(1*9+1*6)x+1*9*6#
#y=x^2+15x+54#

To put it simply:
#y=x*x+9x+6x+9*6#
#y=x^2+15x+54#