What is the standard form of y= x(x+2) -(x+3)^2 y=x(x+2)(x+3)2?

1 Answer
Apr 10, 2018

y=-4x-9y=4x9

Explanation:

Well, this depends on what your standard form is. The practical standard form of a second-power parabola would go like this: y=ax^2+bx+cy=ax2+bx+c . If you want to use this standard form, it will go like this:

y=x(x+2) -(x+3)^2y=x(x+2)(x+3)2

y = (x^2 +2x)-(x^2+6x+9)y=(x2+2x)(x2+6x+9)

y=-4x-9y=4x9

So, in this problem, you have a basic, non-exponential form.