What is the standard form of $y = (x - x^{2}) (x + 8) - {(x + 8)}^{3}$ $y= (x-x^2)(x+8) -(x+8)^3$ ?

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Answer 1 · 2018-08-11T14:31:35

$- 2 x^{3} - 31 x^{2} - 184 x - 512$ $-2x^3 - 31x^2 - 184x - 512$

$(x - x^{2}) (x + 8) - {(x + 8)}^{3}$ $(x - x^2) (x + 8) - (x + 8)^3$

$- (x + 8) [x^{2} - x + {(x + 8)}^{2}]$ $-(x + 8) [x^2 - x + (x + 8)^2]$

$- (x + 8) (x^{2} - x + x^{2} + 16 x + 64)$ $-(x + 8) (x^2 - x + x^2 + 16x + 64)$

$- (x + 8) (2 x^{2} + 15 x + 64)$ $-(x + 8) (2x^2 + 15x + 64)$

$- 2 x^{3} - 31 x^{2} - 184 x - 512$ $-2x^3 - 31x^2 - 184x - 512$

What is the standard form of y=(x−x2)(x+8)−(x+8)3y= (x-x^2)(x+8) -(x+8)^3?