# What is the sum of all the integers between sqrt8 and sqrt67?

$33$
As $\sqrt{8} < \sqrt{9} = 3 , \mathmr{and} \sqrt{67} > \sqrt{64} = 8$,
so the integers between $\sqrt{8}$ and $\sqrt{67}$ are $3 , 4 , 5 , 6 , 7 , 8$
Sum $= 3 + 4 + 5 + 6 + 7 + 8 = 33$