What is the sum of the arithmetic series 1,2,3,4...80?

3 Answers

It is an arithmetic series with first term #a_1=1# and ratio #r=1#
hence

#S_80=(80/2)*(1+80)=3240#

Feb 11, 2016

Answer:

#3240#

Explanation:

The sum of a finite arithmetic sequence is equal to the number of terms multiplied by the average term. The average term is the same as the average of the first and last term.

So in our example:

#sum_(n=1)^80 n = 80 * (1+80)/2 = 40*81 = 3240#

Feb 11, 2016

Answer:

#3240#

Explanation:

A good way to envision how to do this is to imagine pairs:

Start with the largest and smallest terms of the sequence: #80# and #1#.

#80+1=81#

The next largest and smallest are #79# and #2#, which have the same sum.

#79+2=81#

We can start listing these pairs:

#80+1=81#
#79+2=81#
#78+3=81#
#77+4=81#
#76+5=81#

#..."continue"...#

#43+38=81#
#42+39=81#
#41+40=81#

In total, there are #40# pairs since #80/2=40#.

#40# pairs of #81# each is #40xx81=color(red)3240#.