Question

What is the temperature change in 224 g of water upon the absorption of 55 kJ of heat, the specific heat of water is 4.18 J/g °C?

Answer 1

`DeltaT = 58.7^oC`

Explanation:

To obtain the change in temperature, let's use the equation below:

In this question, heat has units of kJ, which does not match up with the units given in the image above. So what we can do first is convert kJ to J by multiplying that value of `q` by 1000 using the conversion factor below:

Here are the variables that we know:

`Q` = `55cancel"kJ"xx(1000J)/(1cancel"kJ")` = 55,000 J
`m` = 224 g
`C` = `4.18J/(gxx^oC)`

All we have to do is rearrange the equation to solve for `Delta T`. This can be accomplished by dividing both sides by `C` and `m` to get `Delta T` by itself like this:

`DeltaT = Q/(mxxC)`

Now, we just plug in the known values:

`DeltaT= (55,000cancelJ)/(224cancelgxx4.18cancelJ/cancel"g"xx^oC)`

`DeltaT = 58.7^oC`