# What is the temperature, in °C, of 0.938 moles of #Cl_2# gas with a pressure of 3.24 atm and volume of 9.31 L?

##### 1 Answer

Apr 11, 2017

Using

#### Explanation:

P = pressure

V = volume in liters

n = moles

R = the universal gas constant, which is different depending on the unit of pressure

T = temperature in Kelvin

So for this question

P = 3.24 atm

V = 9.31 L

n = .938

R = .0821

(3.24)(9.31) = (.938)(.0821)(T)

30.16 = 0.077T

T = 391.7 K

To convert Kelvin to Celsius, subtract 273.

391.7 - 273 = 118.7 C