# What is the the theoretical mass of tin formed from 302 g of tinstone?

Feb 5, 2018

I think you mean $\text{cassiterite}$, $S n {O}_{2}$....

#### Explanation:

And, as usual, carbon was historically used as the reductant....(I don't know what they use today...)

$S n {O}_{2} \left(s\right) + C \left(s\right) \stackrel{\Delta}{\rightarrow} S n \left(l\right) + C {O}_{2} \left(g\right) \uparrow$

"Moles of cassiterite"=(302*g)/(150.71*g*mol^-1)=??*mol

And so we get $2 \cdot m o l$ of tin from complete reduction....a mass of $2 \cdot m o l \times 118.7 \cdot g \cdot m o {l}^{-} 1 = 238 \cdot g$...