Question

What is the the theoretical mass of tin formed from 302 g of tinstone?

Answer 1

I think you mean `"cassiterite"`, `SnO_2`....

Explanation:

And, as usual, carbon was historically used as the reductant....(I don't know what they use today...)

`SnO_2(s) + C(s) stackrel(Delta)rarr Sn(l) + CO_2(g)uarr`

`"Moles of cassiterite"=(302*g)/(150.71*g*mol^-1)=??*mol`

And so we get `2*mol` of tin from complete reduction....a mass of `2*molxx118.7*g*mol^-1=238*g`...