What is the the theoretical mass of tin formed from 302 g of tinstone?

1 Answer
Feb 5, 2018

Answer:

I think you mean #"cassiterite"#, #SnO_2#....

Explanation:

And, as usual, carbon was historically used as the reductant....(I don't know what they use today...)

#SnO_2(s) + C(s) stackrel(Delta)rarr Sn(l) + CO_2(g)uarr#

#"Moles of cassiterite"=(302*g)/(150.71*g*mol^-1)=??*mol#

And so we get #2*mol# of tin from complete reduction....a mass of #2*molxx118.7*g*mol^-1=238*g#...