What is the theoretical yield of solid product when 25.5 ml of 0.150 M lead (II) nitrate is mixed with 30.0 ml of 0.200 M NaOH?
We have the stoichiometric reaction above. I also happen to know that hydroxides are generally insoluble (hence I can predict that the lead hydroxide will precipitate).
We can find the molar quantities of each reagent.
I could rewrite the solubility reaction as a net ionic equation by removing the aqueous species:
The sodium and nitrate ions will remain in solution, and are just along for the ride.