What is the total amount of heat required to completely melt 347 grams of ice at its melting point?

Question

30538 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-03T20:13:16

Well, I will supply the latent heat of fusion for ice......

We interrogate the physical change......

#H_2O(s) +Deltararr H_2O(l)#

Clearly this process is ENDOTHERMIC, and this site reports that the latent heat of fusion for ice is #334*kJ*kg^-1#.

We have a mass of #347*g# of ice, so we take the product.......

#347xx10^-3*kgxx334*kJ*kg^-1=+115.9*kJ#.

Note that BOTH the ICE AND the WATER are assumed to be at #0# #""^@C#.