What is the total amount of heat required to completely melt 347 grams of ice at its melting point?

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Answer 1 · 2017-08-03T20:13:16

Well, I will supply the latent heat of fusion for ice......

We interrogate the physical change......

#H_2O(s) +Deltararr H_2O(l)#

Clearly this process is ENDOTHERMIC, and this site reports that the latent heat of fusion for ice is #334*kJ*kg^-1#.

We have a mass of #347*g# of ice, so we take the product.......

#347xx10^-3*kgxx334*kJ*kg^-1=+115.9*kJ#.

Note that BOTH the ICE AND the WATER are assumed to be at #0# #""^@C#.