What is the total amount of heat required to completely melt 347 grams of ice at its melting point?

1 Answer
Aug 3, 2017

Answer:

Well, I will supply the latent heat of fusion for ice......

Explanation:

We interrogate the physical change......

#H_2O(s) +Deltararr H_2O(l)#

Clearly this process is ENDOTHERMIC, and this site reports that the latent heat of fusion for ice is #334*kJ*kg^-1#.

We have a mass of #347*g# of ice, so we take the product.......

#347xx10^-3*kgxx334*kJ*kg^-1=+115.9*kJ#.

Note that BOTH the ICE AND the WATER are assumed to be at #0# #""^@C#.