# What is the total amount of heat required to completely melt 347 grams of ice at its melting point?

Aug 3, 2017

Well, I will supply the latent heat of fusion for ice......

#### Explanation:

We interrogate the physical change......

${H}_{2} O \left(s\right) + \Delta \rightarrow {H}_{2} O \left(l\right)$

Clearly this process is ENDOTHERMIC, and this site reports that the latent heat of fusion for ice is $334 \cdot k J \cdot k {g}^{-} 1$.

We have a mass of $347 \cdot g$ of ice, so we take the product.......

$347 \times {10}^{-} 3 \cdot k g \times 334 \cdot k J \cdot k {g}^{-} 1 = + 115.9 \cdot k J$.

Note that BOTH the ICE AND the WATER are assumed to be at $0$ ""^@C.