What is the total mass in grams of 0.013 mole of I_2?

Mar 15, 2017

$\text{3.3 g}$

Explanation:

The key here is the molar mass of iodine, which is listed as

M_ ("M I"_2) = "253.81 g mol"^(-1)

The thing to remember about the molar mass of a chemical substance is that you can use it as a conversion factor to go from moles to grams or vice versa.

In other words, the molar mass allows you to figure out how many grams are needed in order to have exactly $1$ mole of a given substance.

In this case, you need $\text{253.81 g}$ of iodine to have exactly $1$ mole of iodine.

This means that $0.013$ moles of iodine would be equivalent to

$0.013 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{moles I"_2))) * overbrace("253.81 g"/(1color(red)(cancel(color(black)("mole I"_2)))))^(color(blue)("the molar mass of I"_2)) = color(darkgreen)(ul(color(black)("3.3 g}}}}$

The answer is rounded to two sig figs, the number of sig figs you have for the number of moles of iodine.