What is the value for #f(x)=3^(2x+1)# when #x=1/2#?

1 Answer
Jim G.
Feb 23, 2017

#f(1/2)=9#

Explanation:

To evaluate f (x) for #x=1/2# substitute this value into f( x).

#f(x)=3^(2x+1)#

#rArrf(color(red)(1/2))=3^(((2xxcolor(red)(1/2))+1)#

#color(white)(xxxxxxxx)=3^((1+1))#

#color(white)(xxxxxxxx)=3^2#

#color(white)(xxxxxxxx)=9#

Related questions
Impact of this question
3122 views around the world
You can reuse this answer
Creative Commons License