# What is the value of 6x^2+4x+8 when x=7?

The value of the trinomial $6 {x}^{2} + 4 x + 8$ when $x = 7$ is $330$
The variable in this question is $x$, which in this case we are told has a value of $7$ because we are given $x = 7$. By substituting this value for $x$ into the trinomial in place of $x$ we get:
$6 {\left(7\right)}^{2} + 4 \left(7\right) + 8$
$6 \left(49\right) + 28 + 8$
$294 + 28 + 8 = 330$