What is the value of #6x+5(7+4x)# if #x=4# and #s=-8#?

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Answer 1 · 2018-05-07T17:19:09

The solution is #6x + 5(7+4x)= 139# when #x=4#

The value for #6x + 5(7+4x)# when #x=4# and #s=-8#

Begin by substituting the value #4# in for each #x#

#6(4) + 5(7+4(4))

Solve inside the parenthesis first.

#6(4) +5(7+16)#

#6(4) +5(23)#

Now complete the multiplication

#24 + 115#

Now add

#139#