What is the value of #h(5)# when #h(s) = 2|-2/3s - 6|#?

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Answer 1 · 2017-03-30T02:29:49

See the entire solution process below:

To solve evaluate this function for #h(5)# we must substitute #color(red)(5)# for each occurrence of #s# in the function #h(s)#:

#h(color(red)(s)) = 2abs(-2/3color(red)(s) - 6)# becomes:

#h(color(red)(5)) = 2abs((-2/3 xx color(red)(5)) - 6)#

#h(color(red)(5)) = 2abs(-10/3 - 6)#

#h(color(red)(5)) = 2abs(-10/3 - (3/3 xx 6)#

#h(color(red)(5)) = 2abs(-10/3 - 18/3)#

#h(color(red)(5)) = 2 xx abs(-28/3)#

#h(color(red)(5)) = 2 xx 28/3#

#h(color(red)(5)) = 56/3#