What is the value of #log_2 5# between two consecutive integers?

1 Answer
Mar 16, 2018

#2 < log_2 5 < 3#

Explanation:

Note that #log_2 x# is a strictly monotonically increasing function from #(0, oo)# onto #(-oo, oo)#

We find:

#2^2 = 4 < 5 < 8 = 2^3#

Since #log_2# is a strictly monotonically increasing function, we can take the logarithm base #2# of all parts of this inequality to get:

#2 = log_2 4 < log_2 5 < log_2 8 = 3#