What is the value of #t# if #f(t)=86.14t-95.16# when #f(t)=-594.772#?

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Answer 1 · 2017-04-17T22:16:39

See the entire solution process below:

To solve this equate #86.14t - 95.16# to #-594.772# and solve for #t#;

#86.14t - 95.16 = -594.772#

#86.14t - 95.16 + color(red)(95.16) = -594.772 + color(red)(95.16)#

#86.14t - 0 = -499.612#

#86.14t = -499.612#

#(86.14t)/color(red)(86.14) = -499.612/color(red)(86.14)#

#(color(red)(cancel(color(black)(86.14)))t)/cancel(color(red)(86.14)) = -5.8#

#t = -5.8#

#t# is #color(red)(-5.8)# when #f(t) = -594.772#