What is the vertex of the graph of #y=-(x-2)^2+3#? Precalculus Geometry of a Parabola Graphing Parabolas 1 Answer Plmz1221 Aug 29, 2014 Where the general form of a parabola is #y=a(x+h)+k# the vertex is #(-h,k)# In this case #h=-2# and #k=3# so the vertex is #(2,3)# Answer link Related questions What is the graph of the parabola represented by #y=2x^2-8x+9#? What is the parent graph of a parabola? How do I find the axis of the graph of the function #f(x)=4x^2+8x+7#? What is the graph of #f(x)=-2x^2+7x+4#? What is the x-intercept of the graph of #y=x^2-4x+4#? What is the vertex of the graph of #y=x^2+3x-4#? What is the vertex of the graph of #y=2(x-3)^2-7#? What is the axis of symmetry of the graph of #y=-(x+3)^2-6#? How do I graph #y=x^2-2x-3#? How do I graph #y=x^2-6x+5#? See all questions in Graphing Parabolas Impact of this question 6083 views around the world You can reuse this answer Creative Commons License