What is the vertex of the parabola given by the equation, y=-2x^2-12x-16?

1 Answer
Jun 6, 2016

V(-3;2)

Explanation:

Let y=ax^2+bx+c=0 the general equation of a parabola

The vertex is obtained by:

V(-b/(2a); (4ac-b^2)/(4a))

so

V(-(-12)/(2(-2));(4(-2)(-16)-(-12)^2)/(4(-2)))
V(-3;(128-144)/(-8))
V(-3;-16/-8)
V(-3;2)