Question

What is the vertex of the parabola given by the equation, `y=-2x^2-12x-16`?

Answer 1

`V(-3;2)`

Explanation:

Let `y=ax^2+bx+c=0` the general equation of a parabola

The vertex is obtained by:

`V(-b/(2a); (4ac-b^2)/(4a))`

so

`V(-(-12)/(2(-2));(4(-2)(-16)-(-12)^2)/(4(-2)))`
`V(-3;(128-144)/(-8))`
`V(-3;-16/-8)`
`V(-3;2)`