What is the vertex of #y = 2(3x+2)^2 + 5#?

1 Answer
Alan P.
Dec 18, 2015

Vertex: #(-2/3,5)#

Explanation:

General vertex form:
#color(white)("XXX")y=m(x-a)^2+b#
with vertex at #(a,b)#

Converting #y=2(3x+2)^2+5# into "vertex form"
#color(white)("XXX")y=2(3(x+2/3))^2+5#

#color(white)("XXX")y=2(9)(x+2/3)^2+5#

#color(white)("XXX")y=18(x-(-2/3))^2+5#

Related questions
Impact of this question
335 views around the world
You can reuse this answer
Creative Commons License