# What is the volume, in liters, of 0.500 mol of C_3H_8 gas at STP?

Aug 20, 2016

$\textcolor{b l u e}{\text{11.2 L}}$

#### Explanation:

Because we are at standard temperature and pressure and are given only one set of conditions, we can to use the ideal gas law equation:

I should mention that the pressure does not always have units of atm, it depends on the units of pressure given in the gas constant.

List your known and unknown variables.

color(purple)("Knowns:"
- Number of moles
- Temperature
- Pressure

color(blue)("Unknowns:"
Volume of ${C}_{3} {H}_{8} \left(g\right)$

At STP, the temperature is 273K and the pressure is 1 atm.

Let's rearrange the equation to solve for V:

$\frac{n \times R \times T}{P}$

V = (0.500cancel"mol"xx0.0821Lxxcancel(atm)/cancel(molxxK)xx273cancelK)/(1cancel(atm)

$V = 11.2 L$