Question

What is the volume (in liters) of 2.5 moles of oxygen gas measured at 250C and a pressure of 104.5 kpa?

Answer 1

`V=(nRT)/P` `~=` `100*L`

Explanation:

Of course you must choose the appropriate Gas constant. Here it is `8.314*L*kPa*K^-1*mol^-1`.

`"Volume"` `=(2.5*cancel(mol)xx8.314*L*cancel(kPa)*cancel(K^-1)*cancel(mol^-1)xx523*cancelK)/(104.5*cancel(kPa))`

`=` `??L`