What is the volume of 19.87 mol of ammonium chloride (#NH_4Cl#) at STP?

1 Answer
Jun 8, 2016

Answer:

445.3 L of #NH_4Cl#

Explanation:

Since we are at STP, we would use the ideal gas law equation
#PxxV = nxxRxxT#.

  • P represents pressure (must have units of atm)
  • V represents volume (must have units of liters)
  • n represents the number of moles
  • R is the proportionality constant (has units of #(Lxxatm)/ (molxxK)#)
  • T represents the temperature, which must be in Kelvins.

Now what you want to do is list your known and unknown variables. Our only unknown is the volume of #NH_4Cl#. Our known variables are P,n,R, and T.

Since we are at STP, the temperature is 273K and the pressure is 1 atm. We are given moles and the proportionality constant, R, is equal to 0.0821 #(Lxxatm)/ (molxxK)#
Now all we have to do is rearrange the equation and solve for V like so:
#V = (nxxRxxT)/P#
#V = (19.87molxx0.0821(Lxxatm)/(molxxK)xx(273K))/(1atm)#
#V = 445.3 L#