# What is the volume of a gas at RTP and STP?

Jul 9, 2017

Well, you'll have to give your equation of state if you want my answer to be more accurate... But since you did not mention ideality, I will have to assume an ideal gas...

We also utilize the latest RTP and STP from IUPAC:

• RTP: ${25}^{\circ} \text{C}$ and $\text{1 bar}$, just like for the thermodynamic standard state
• STP: ${0}^{\circ} \text{C}$ and $\text{1 bar}$, after 1982, i.e. today...

And thus, its MOLAR volume is given by

$\textcolor{b l u e}{{\overline{V}}_{R T P}^{\text{id}}} = \frac{R {T}_{R T P}}{P}$

= (("0.083145 L"cdot"bar/mol"cdot"K")("298.15 K"))/("1 bar")

$=$ $\textcolor{b l u e}{\text{24.790 L/mol}}$

or

$\textcolor{b l u e}{{\overline{V}}_{S T P}^{\text{id}}} = \frac{R {T}_{S T P}}{P}$

= (("0.083145 L"cdot"bar/mol"cdot"K")("273.15 K"))/("1 bar")

$= \frac{273.15}{298.15} {\overline{V}}_{R T P}^{\text{id}}$

$=$ $\textcolor{b l u e}{\text{22.711 L/mol}}$