Question

What is the volume of gas at 2.00 atm and 200.0 K if its original volume was 300. L at STP?

Answer 1

`"8.20 L"`

Explanation:

Use combined gas law equation

`("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`

`"V"_2 = ("P"_1"V"_1)/"T"_1 × "T"_2/"P"_2`

`"V"_2 = ("1.00 atm × 22.4 L")/("273.15 K") × "200.0 K"/"2.00 atm"`

`"V"_2 = 8.20\ "L"`

Note: I have taken pressure at STP as 1.00 atm which was true until 1982. Since 1982 pressure at STP is taken as 1.00 bar. Click here for more.